3x^2-9x-110=0

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Solution for 3x^2-9x-110=0 equation:



3x^2-9x-110=0
a = 3; b = -9; c = -110;
Δ = b2-4ac
Δ = -92-4·3·(-110)
Δ = 1401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{1401}}{2*3}=\frac{9-\sqrt{1401}}{6} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{1401}}{2*3}=\frac{9+\sqrt{1401}}{6} $

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